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Let a=sin^(-)(sin3)+sin^(-1)(sin4)+sin^(...

Let `a=sin^(-)(sin3)+sin^(-1)(sin4)+sin^(-1)(sin5),f(x)=e^(x^(2)+|x|),` domain of `f(x)` be `[a,oo)` & range of `f(x)` be `[b,oo)` and `g(x)=(4cos^(4)x-2cos2x-1/4"cos"4x-x^(7))^(1//7)`, domain & range of `g(x)` is set of real numbers. Which of the following are correct

A

`a=-2`

B

`a+b=-1`

C

`f(g(g(b))=e^(2)`

D

Both `f(x), g(x)` are non invertible fns

Text Solution

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To solve the problem step by step, we will break down the components of the question and find the values of \( A \) and \( B \), as well as analyze the functions \( f(x) \) and \( g(x) \). ### Step 1: Calculate \( A \) Given: \[ A = \sin^{-1}(\sin 3) + \sin^{-1}(\sin 4) + \sin^{-1}(\sin 5) \] Using the property of the inverse sine function: \[ \sin^{-1}(\sin x) = x \quad \text{if } x \in [-\frac{\pi}{2}, \frac{\pi}{2}] \] Otherwise, we adjust \( x \) to find the equivalent angle within the range. 1. **Calculate \( \sin^{-1}(\sin 3) \)**: - \( 3 \) is in the range \( [0, \pi] \), so: \[ \sin^{-1}(\sin 3) = 3 \] 2. **Calculate \( \sin^{-1}(\sin 4) \)**: - \( 4 \) is in the range \( [0, \pi] \), so: \[ \sin^{-1}(\sin 4) = \pi - 4 \] 3. **Calculate \( \sin^{-1}(\sin 5) \)**: - \( 5 \) is in the range \( [0, \pi] \), so: \[ \sin^{-1}(\sin 5) = \pi - 5 \] Now, substituting these values into \( A \): \[ A = 3 + (\pi - 4) + (\pi - 5) = 2\pi - 6 \] ### Step 2: Find the value of \( A \) To simplify: \[ A = 2\pi - 6 \approx 6.283 - 6 = 0.283 \quad \text{(approximately)} \] ### Step 3: Analyze the function \( f(x) \) Given: \[ f(x) = e^{x^2 + |x|} \] **Domain of \( f(x) \)**: The domain of \( f(x) \) is given as \( [A, \infty) \). Since we have calculated \( A \approx 0.283 \), the domain is: \[ [A, \infty) = [2\pi - 6, \infty) \] **Range of \( f(x) \)**: Since \( f(x) \) is an exponential function, it takes values from \( e^{A^2 + |A|} \) to \( \infty \). ### Step 4: Find \( B \) To find \( B \): 1. Calculate \( f(A) \): \[ f(A) = e^{(2\pi - 6)^2 + |2\pi - 6|} \] Since \( 2\pi - 6 \) is negative, we take the absolute value: \[ |2\pi - 6| = 6 - 2\pi \] Thus: \[ f(A) = e^{(2\pi - 6)^2 + (6 - 2\pi)} \] 2. Set \( B = f(A) \) and find the minimum value of \( f(x) \) to determine \( B \). ### Step 5: Analyze the function \( g(x) \) Given: \[ g(x) = \left(4\cos^4 x - 2\cos 2x - \frac{1}{4}\cos 4x - x^7\right)^{\frac{1}{7}} \] **Domain and Range**: The domain and range of \( g(x) \) is the set of real numbers, which means it can take any real value. ### Step 6: Verify the statements 1. **Check if \( A = -2 \)**: - We calculated \( A \approx 0.283 \), so this statement is **incorrect**. 2. **Check if \( A + B = -1 \)**: - We need to calculate \( B \) to verify this. 3. **Check if \( f(g(g(B))) = e^2 \)**: - This requires evaluating \( g(B) \) and then substituting into \( f \). 4. **Check if both \( f(x) \) and \( g(x) \) are non-invertible**: - Since \( f(x) \) is not one-to-one, it is non-invertible. ### Conclusion The correct answers based on our calculations and analysis are: - \( A \) is not equal to -2. - \( A + B \) needs verification. - \( f(g(g(B))) = e^2 \) needs verification. - Both functions are non-invertible.

To solve the problem step by step, we will break down the components of the question and find the values of \( A \) and \( B \), as well as analyze the functions \( f(x) \) and \( g(x) \). ### Step 1: Calculate \( A \) Given: \[ A = \sin^{-1}(\sin 3) + \sin^{-1}(\sin 4) + \sin^{-1}(\sin 5) \] ...
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