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The equation of a transverse wave travel...

The equation of a transverse wave travelling along a string is given by
`y=0.4sin[pi(0.5x-200t)]` where `y` and `x` are measured in cm and `t` in seconds. Suppose that you clamp the string at two points `L` cm apart and you observe a standing wave of the same wavelength as above transverse wave. For what values of `L` less than `10 cm` is this possible?

A

`2cm`

B

`4cm`

C

`9cm`

D

`8cm`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given wave equation and determine the possible values of \( L \) for which a standing wave can be formed. ### Step-by-Step Solution: 1. **Identify the Wave Equation**: The equation of the transverse wave is given as: \[ y = 0.4 \sin[\pi(0.5x - 200t)] \] 2. **Extract the Wave Number \( k \)**: From the wave equation, we can identify the wave number \( k \): \[ k = 0.5\pi \] 3. **Calculate the Wavelength \( \lambda \)**: The relationship between wave number \( k \) and wavelength \( \lambda \) is given by: \[ k = \frac{2\pi}{\lambda} \] Rearranging this gives: \[ \lambda = \frac{2\pi}{k} \] Substituting \( k = 0.5\pi \): \[ \lambda = \frac{2\pi}{0.5\pi} = 4 \text{ cm} \] 4. **Understand the Condition for Standing Waves**: When the string is clamped at two points \( L \) cm apart, standing waves can form. The distance \( L \) must be a multiple of half the wavelength: \[ L = n \frac{\lambda}{2} \] where \( n \) is a positive integer. 5. **Substitute the Wavelength**: Since \( \lambda = 4 \text{ cm} \), we have: \[ L = n \frac{4}{2} = 2n \text{ cm} \] 6. **Determine Possible Values of \( L \)**: We need to find values of \( L \) that are less than 10 cm: - For \( n = 1 \): \( L = 2 \times 1 = 2 \text{ cm} \) - For \( n = 2 \): \( L = 2 \times 2 = 4 \text{ cm} \) - For \( n = 3 \): \( L = 2 \times 3 = 6 \text{ cm} \) - For \( n = 4 \): \( L = 2 \times 4 = 8 \text{ cm} \) - For \( n = 5 \): \( L = 2 \times 5 = 10 \text{ cm} \) (not valid since \( L < 10 \)) Thus, the possible values of \( L \) that are less than 10 cm are: \[ L = 2 \text{ cm}, 4 \text{ cm}, 6 \text{ cm}, 8 \text{ cm} \] ### Final Answer: The possible values of \( L \) less than 10 cm are: - \( 2 \text{ cm} \) - \( 4 \text{ cm} \) - \( 6 \text{ cm} \) - \( 8 \text{ cm} \)

To solve the problem, we need to analyze the given wave equation and determine the possible values of \( L \) for which a standing wave can be formed. ### Step-by-Step Solution: 1. **Identify the Wave Equation**: The equation of the transverse wave is given as: \[ y = 0.4 \sin[\pi(0.5x - 200t)] ...
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