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A force F acting on a particle varies wi...

A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from

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The correct Answer is:
2
`K_(0)=1/2 alpha x_(0)^(2)`
Kinetic energy just after `3^(rd)` collision `=(1/2)^(6)K_(0)=1/64K_(0)`
`1/64(1/2 alpha x_(0)^(2))impliesx=(x_(0))/8`
`F=alphax=(alpha x_(0))/8=2N`
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