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In the reaction : 3Br(2)+6CO(3)^(2-)+3...

In the reaction :
`3Br_(2)+6CO_(3)^(2-)+3H_(2)Orarr5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)`

A

Bromine is oxidised and carbonate is reduced

B

Bromine is oxidised

C

Bromine is reduced

D

It is disproportionation reaction or autoredox change

Text Solution

Verified by Experts

The correct Answer is:
B, C, D

`Br_(2)(ON=0)` reduces to `Br^(-) (ON=-1)` and oxidises to `BrO_(3)^(-)(ON=+5)`
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