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Two liquids 'A' (molecular mass=40) and ...

Two liquids 'A' (molecular mass=40) and B'=(Molecular mass=20) are partially miscible.When 1 mol of A and 3 mol of B are shaken together and allowed to settle, two layer `L_1 and L_2` are formed as shown in diagram.(Mol)(P)[T]

Layer `'L_1'` contains 0.1 mole fraction of 'A' and layer `'L_2'` contains 0.4 mole fraction of A calculate simple ratio of masses of layer `L_1` to layer `L_2`.If your answer is `x/y` then report as `(x+y)`

Text Solution

Verified by Experts

The correct Answer is:
9
In layer `M`
`n_(A)=x n_(B)=y`
`x/(x+y)=0.2impliesy/x+1=5impliesy/x=4impliesy=4x`
In layer `N` ltbr. `((i-x))/((1-x)(3-y))=0.6`
`(3-y)/(1-x)+1=1/0.6implies(3-y)/(1-x)=4/6=2/3`
`=9-3y=2-2x`
`7=10ximpliesx=0.7, y=2.8`
`w_(M)=0.7xx20+0.7xx4xx40=14+7xx16=126`
`w_(N)=0.3xx20+0.2xx40=14`
`w_(M)//w_(N)=9`
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