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The point at which the tangent to the cu...

The point at which the tangent to the curve `y=x^2-4x` is parallel to x-axis is

A

(0 , 4)

B

(-2 , 4)

C

(2 , 4)

D

(2 , -4)

Text Solution

Verified by Experts

The correct Answer is:
9
`(x-2)/(-1/(sqrt(2)))=(y-1)/(1/(sqrt(2)))=4sqrt(2)` or `-4sqrt(2)`
`:. A(-2,5)` & `B(6, -3)`
`:.` area of `/_\CAB=20`
`implies` sum `=2sqrt(20)=4sqrt(5)`
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