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If y=f(x) is solution of differentiable ...

If `y=f(x)` is solution of differentiable equation `(dy)/(dx)=y/x((1-3x^(2)y^(3)))/((2x^(2)y^(3)+1))`, then (`f(x).x)^(3)` is equal to

A

`x+cy`

B

`2x+cy`

C

`x^(2)+cy`

D

`x^(3)+cy^(2)`

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The correct Answer is:
To solve the given differential equation and find the value of \((f(x) \cdot x)^3\), we will follow these steps: ### Step 1: Write down the differential equation We start with the given differential equation: \[ \frac{dy}{dx} = \frac{y}{x} \cdot \frac{1 - 3x^2 y^3}{2x^2 y^3 + 1} \] ### Step 2: Cross-multiply to rearrange the equation We can rearrange the equation by cross-multiplying: \[ (2x^2 y^3 + 1) dy = y(1 - 3x^2 y^3) \frac{dx}{x} \] ### Step 3: Expand and rearrange the terms Expanding both sides, we get: \[ 2x^2 y^3 dy + dy = y \left( \frac{dx}{x} - 3x^2 y^3 \frac{dx}{x} \right) \] This simplifies to: \[ 2x^2 y^3 dy + dy = y \frac{dx}{x} - 3x^2 y^4 \frac{dx}{x} \] ### Step 4: Collect terms involving \(dy\) and \(dx\) Rearranging gives us: \[ 2x^2 y^3 dy + 3x^2 y^4 \frac{dx}{x} = y \frac{dx}{x} - dy \] This can be rearranged to: \[ 2x^2 y^3 dy + 3x^2 y^4 \frac{dx}{x} + dy = y \frac{dx}{x} \] ### Step 5: Factor out common terms Factoring out common terms leads us to: \[ (2x^2 y^3 + 3x^2 y^4) dy = y \frac{dx}{x} - dy \] ### Step 6: Separate variables We can separate the variables: \[ \frac{dy}{y} = \frac{dx}{x(2x^2 y^3 + 3x^2 y^4)} \] ### Step 7: Integrate both sides Integrating both sides gives: \[ \int \frac{dy}{y} = \int \frac{dx}{x(2x^2 y^3 + 3x^2 y^4)} \] ### Step 8: Solve the integrals The left side integrates to: \[ \ln |y| = \ln |x| + C \] Exponentiating both sides, we have: \[ y = kx \quad \text{(where \(k = e^C\))} \] ### Step 9: Substitute back to find \(f(x)\) Substituting \(y = f(x) = kx\) into our equation gives: \[ f(x) \cdot x = kx^2 \] ### Step 10: Find \((f(x) \cdot x)^3\) Now we compute: \[ (f(x) \cdot x)^3 = (kx^2)^3 = k^3 x^6 \] ### Final Result Thus, we have: \[ (f(x) \cdot x)^3 = k^3 x^6 \] And since \(k\) is a constant that can be absorbed into the constant of integration, we can express the final answer as: \[ x^6 + C \]

To solve the given differential equation and find the value of \((f(x) \cdot x)^3\), we will follow these steps: ### Step 1: Write down the differential equation We start with the given differential equation: \[ \frac{dy}{dx} = \frac{y}{x} \cdot \frac{1 - 3x^2 y^3}{2x^2 y^3 + 1} \] ...
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