If y=2 is directrix and (0,1) be the ver...

If `y=2` is directrix and `(0,1)` be the vertex of parabola `x^(2)+lamday+mu=0` then, `(lamda-mu)=`?

Verified by Experts

The correct Answer is:

8

`:' x^(2)=-4(y-1)` has directrix
`y-1+1`
`y=2`
`: lamda=4`
`mu=-4`
`lamda-mu=8`

Similar Questions

Explore conceptually related problems

If y=2 is the directrix and (0,1) is the vertex of the parabola x^2+lambday+mu=0 , then (a) lambda=4 (b) mu=8 (c) lambda=-8 (d) mu=4

The vertex of the parabola x^(2)+12x-9y=0 is

The vertex of the parabola y^(2)+4x-2y+3=0 is

The vertex of the parabola y^2+6x-2y+13=0 is

The vertex of the parabola y^(2)-2x+8x-23=0 is

The vertex of the parabola y^(2) - 4y - 16 x - 12 = 0 is

The directrix of the parabola x^2-4x-8y + 12=0 is

Find vertex, focus, directrix and latus rectum of the parabola y^(2)+4x+4y-3=0 .