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Velocity of a particle of mass 2 kg chan...

Velocity of a particle of mass `2 kg` change from `vecv_(1) =-2hati-2hatjm/s` to `vecv_(2)=(hati-hatj)m//s` after colliding with as plane surface.

A

The angle made by the plane surface with the positive `x`-axis is `90^(@)+tan^(-1)(1/3)`

B

The angle made by the plane surface with the positive `x`- axis is `tan^(-1)(1/3)`

C

The direction of change in momentum make an angle `tan^(-1)(1/3)` with the positive `x`-axis

D

The direction of charge in momentum makes an angle `90^(@)+tan^(-1)(1/3)` with the plane surface.

Text Solution

Verified by Experts

The correct Answer is:
A, C
`DeltavecP=2(hati-hatj)-(-2hati-2hatj)`
`=6hati+2hatj` kg-m/s
So `DeltavecP` makes angle `tan^(-1)(1/3)` with positive `x`- axis which is also the direction of normal force exerted on the ball. So the plane surface makes an angle `(pi)/2+tan^(-1)(1/3)` with positive `x`- axis.
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