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A rope AB of linear mass density lamda i...

A rope `AB` of linear mass density `lamda` is placed on a quarter vertical fixed disc of radius `R` as shown in the figure. The surface between the disc and rope is rough such that the rope is just is equilibrium. Gravitational acceleration is `g`. Choose the correct option (s).

A

Coefficient of static friction between rope and disc is `mu=1`

B

Coefficient of static friction between rope and disc is `mu=1/(sqrt(2))`

C

Maximum tension in the rope is at the top most point `A` of the rope

D

Maximum tension in the rope is `lamdaRg(sqrt(2)-k1)`

Text Solution

Verified by Experts

The correct Answer is:
A, D

For equilibrium
`lamda Rg int_(0)^((pi)/2) cos theta d theta =mu lamda Rg int_(0)^((pi)/2) sin theta d theta`
`:.mu=1`
At the position of maximum tension in the rope
`lamda R d thetag cos theta=mu(lamda R d theta g sin theta)`
`:. theta=45^(@)`
At any `theta`
`dT=lamda R d theta g cos theta -mu lamda d theta g sin theta`
`int_(0)^(T_("max")) dT =lamda Rg int_(0)^((pi)/4) (cos theta-sintheta)d theta`
`T_("max")=lamda Rg[sintheta+costheta]_(0)^((pi)/4)=lamda Rg[1/(sqrt(2))+1/(sqrt(2))-1]=lamdaRg(sqrt(2)-1)`
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