Home
Class 12
CHEMISTRY
Some inert gas is added at constant volu...

Some inert gas is added at constant volume to the following reaction at equilibrium
`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)` predict the effect of adding the inert gas:

A

Addition of `NH_(4)HS(s)` at equilibrium increases the concentration of `NH_(3)(g)`.

B

Addition of `NH_(3)(g)` at equilibrium decreases the concentration of `H_(2)S(g)`

C

`K_(P)` is independent of the amount of `NH_(4)HS(s)`

D

Increase inn temperature change the `K_(P)` of this reaction.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`K_(P)=P_(NH_(30)xxP_(H_(2)S)`
Addition of `NH_(4)HS` (s) at equilibrium does not change the concentration of `NH_(3)(g)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

If helium gas is added at constant pressure to the following reaction at equilibrium CO(g) + 3H_2(g) hArr CH_4(g) + H_2O(g) , then

On adding NH_4HS in following equilibrium NH_4HS(s)hArr NH_3(g) +H_2S(g)

In the equilibrium NH_(4) HS_(s) hArr NH_(3(g)) + H_(2) S_((g)) . the forward reaction can be favoured by

Consider the following reaction at equilibrium: NH_4HS(s)

By adding inert gas at a constant volume, which of the following equilibrium will not be affected?

For NH_(4)HS(s)hArr NH_(3)(g)+H_(2)S(g) If K_(p)=64atm^(2) , equilibrium pressure of mixture is

On decomposition of NH_(4)HS , the following equilibrium is estabilished: NH_(4) HS(s)hArrNH_(3)(g) + H_(2)S(g) If the total pressure is P atm, then the equilibrium constant K_(p) is equal to

On addition of inert gas at constant volume into container in which following equilibrium is established : PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) . Which is incorrect :-

What will happen if an inert gas is added at constant volume to the system 2Hl (g) hArr (g) + I_2 (g) ?

In one experiment, certain amount of NH_(4)I(s) was heated rapidly in a closed container at 357^(@)C . The following equilibrium was established: NH_(4)I(s) hArrNH_(3)(g)+HI(g) but the pressure gradually increases further (when the excess solid residue remains in the vessel) owing to the dissociation of HI. Calculate the final pressure developed at equilibrium. . 2HI(g)rarrH_(2)(g)+l_(2)(g) K_(C)=0.065 at 357 ∘ C.