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The hydroxide which is soluble in excess...

The hydroxide which is soluble in excess of NaOH is _______ `[Zn(OH)_(2)//Fe(OH)_(3)//Fe(OH)_(2)]`

Text Solution

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The correct Answer is:
3
`Al(OH)_(3)+NaOH to underset(("soluble"))(NaAlO_(2))+2H_(2)O`
`Zn(OH)_(2)+2NaOHto underset(("soluble"))(Na_(2)ZnO_(2))+2H_(2)O`
`Sn(OH)_(2)+2NaOHto underset(("soluble"))(Na_(2)SnO_(2))+2H_(2)O`
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