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Obtain the equaiton of straight lines pa...

Obtain the equaiton of straight lines passing through the point `A (2, 0)` and making an angle of `45^0` with the tangent at `A` to the circle `(x+2)^2 + (y+3)^2 = 25`. Find the equation of the circle each of radius 3, whose centres are on these straight lines each at a distance of `5sqrt(2)` units from `A`.

A

`(x-1)^(2)+(y-7)^(2)=9`

B

`(x-3)^(2)+(y+7)^(2)=9`

C

`(x-9)^(2)+(y-1)^(2)=9`

D

`(x+9)^(2)+(y+1)^(2)=9`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

Equation of tangent at `A` is `4x-3y-8=0`
Let `y=m(x-2)` in line thro `(2,0)` and `m=-7` or `1/7`
We have `(x-2)/(- 1/(sqrt(50)))=y/(7/(sqrt(50)))=5sqrt(2)`
`implies` Centre of circle are `(1,7), (3,-7),(9,1)` and `d(-5,-1)`
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