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Find the area of a quadrant of a circle ...

Find the area of a quadrant of a circle whose radius is 14 cm.

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To find the area of a quadrant of a circle with a radius of 14 cm, we can follow these steps: ### Step 1: Identify the radius Let the radius \( r \) of the circle be given as: \[ r = 14 \, \text{cm} \] **Hint:** Remember that the radius is the distance from the center of the circle to any point on its circumference. ### Step 2: Calculate the area of the full circle The formula for the area \( A \) of a circle is: \[ A = \pi r^2 \] Substituting the value of \( r \): \[ A = \pi (14)^2 \] \[ A = \pi \times 196 \] **Hint:** Use the value of \( \pi \) as \( \frac{22}{7} \) for easier calculations. ### Step 3: Substitute the value of \( \pi \) Now, substituting \( \pi \) into the area formula: \[ A = \frac{22}{7} \times 196 \] **Hint:** You can simplify \( 196 \) as \( 28 \times 7 \). ### Step 4: Simplify the area calculation \[ A = \frac{22}{7} \times (28 \times 7) \] The \( 7 \) in the numerator and denominator cancels out: \[ A = 22 \times 28 \] **Hint:** Break down \( 22 \times 28 \) into smaller multiplications if needed. ### Step 5: Calculate \( 22 \times 28 \) Calculating: \[ 22 \times 28 = 616 \, \text{cm}^2 \] **Hint:** You can also use the distributive property: \( 22 \times (20 + 8) = 440 + 176 \). ### Step 6: Find the area of the quadrant Since a quadrant is one-fourth of the circle, we divide the area of the circle by 4: \[ \text{Area of the quadrant} = \frac{616}{4} \] **Hint:** Dividing by 4 can be done by halving twice. ### Step 7: Calculate the area of the quadrant \[ \text{Area of the quadrant} = 154 \, \text{cm}^2 \] ### Final Answer The area of the quadrant of the circle is: \[ \boxed{154 \, \text{cm}^2} \]

To find the area of a quadrant of a circle with a radius of 14 cm, we can follow these steps: ### Step 1: Identify the radius Let the radius \( r \) of the circle be given as: \[ r = 14 \, \text{cm} \] **Hint:** Remember that the radius is the distance from the center of the circle to any point on its circumference. ...
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