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Which of the following is/are true?...

Which of the following is/are true?

A

`100^(300)lt300!`

B

`sqrt(300^(300))lt 300!`

C

`100^(300)gt300!`

D

`sqrt(300^(300))gt300!`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given statements are true, we need to analyze the inequalities involving \(100^{300}\), \(300!\), and \(\sqrt{300^{300}}\). ### Step 1: Understanding the relationship between \(n!\) and \(n^n\) We know from the properties of factorials and exponentials that: \[ n! > \frac{n^n}{e^n} \] This implies that: \[ n! > \left(\frac{n}{e}\right)^n \] For \(n = 300\): \[ 300! > \left(\frac{300}{e}\right)^{300} \] ### Step 2: Approximating \(e\) Since \(e \approx 2.718\), we can approximate it as \(3\) for simplicity in inequalities: \[ 300! > \left(\frac{300}{3}\right)^{300} = 100^{300} \] Thus, we conclude: \[ 300! > 100^{300} \] ### Step 3: Evaluating the first statement The first statement is: \[ 100^{300} < 300! \] From our previous conclusion, this statement is **true**. ### Step 4: Evaluating the second statement Next, we need to evaluate: \[ \sqrt{300^{300}} < 300! \] We can simplify \(\sqrt{300^{300}}\): \[ \sqrt{300^{300}} = 300^{150} \] Now, we need to check if: \[ 300^{150} < 300! \] Using the earlier result \(300! > 100^{300}\), we can relate this to \(300^{150}\): Since \(100^{300} = (10^2)^{300} = 10^{600}\) and \(300^{150} = (3 \times 100)^{150} = 3^{150} \times 100^{150}\), we can see that \(300^{150}\) is significantly smaller than \(300!\) due to the rapid growth of factorials. Thus, we conclude: \[ 300^{150} < 300! \] ### Step 5: Final conclusion Both statements are true: 1. \(100^{300} < 300!\) 2. \(\sqrt{300^{300}} < 300!\) ### Summary of Findings The true statements are: - \(100^{300} < 300!\) - \(\sqrt{300^{300}} < 300!\)

To determine which of the given statements are true, we need to analyze the inequalities involving \(100^{300}\), \(300!\), and \(\sqrt{300^{300}}\). ### Step 1: Understanding the relationship between \(n!\) and \(n^n\) We know from the properties of factorials and exponentials that: \[ n! > \frac{n^n}{e^n} ...
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