sum(k=1)^ook(1-1/n)^(k-1)=>? a.n(n-1)...

`sum_(k=1)^ook(1-1/n)^(k-1)=>? a.`n(n-1)` b. `n(n+1)` c. `n^2` d. `(n+1)^2`

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The correct Answer is:

1

`(r^(2)+2)(r+1)!+2r(r+1)!=(r+1)(r+2)!-r(r+1)!`

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