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Which of the following an reaction with ...

Which of the following an reaction with `H_(2)S` will produce metal sulphide?

A

`COCl_(2)`

B

`CuCl_(2)`

C

`[Cd(CN)_(4)]^(2-)`

D

`[Zn(OH)_(4)]^(2-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds will produce a metal sulfide when reacted with hydrogen sulfide (H₂S), we need to analyze each option provided. ### Step-by-step Solution: 1. **Identify the Compounds**: The options given are: - A) COCl₂ - B) Cd(CN)₄²⁻ - C) Zn(OH)₂²⁻ 2. **Analyze COCl₂**: - COCl₂ is known as phosgene, which does not contain any metal. Therefore, it cannot react with H₂S to produce a metal sulfide. - **Conclusion**: COCl₂ will **not** produce a metal sulfide. 3. **Analyze Cd(CN)₄²⁻**: - This is a coordination complex containing cadmium (Cd) as the metal. When reacted with H₂S, the metal can potentially be replaced, but the presence of cyanide (CN⁻) ligands means that the metal is not free to react directly with H₂S to form a sulfide. - **Conclusion**: Cd(CN)₄²⁻ will **not** produce a metal sulfide. 4. **Analyze Zn(OH)₂²⁻**: - This is also a coordination complex where zinc (Zn) is the metal. Similar to the previous case, the hydroxide (OH⁻) ligands may prevent the direct formation of a metal sulfide when reacted with H₂S. - **Conclusion**: Zn(OH)₂²⁻ will **not** produce a metal sulfide. 5. **Final Conclusion**: - The only compound that has the potential to produce a metal sulfide when reacted with H₂S is COCl₂, but since it does not contain any metal, it cannot produce a metal sulfide. - Therefore, none of the options provided will produce a metal sulfide when reacted with H₂S. ### Final Answer: None of the given options will produce a metal sulfide when reacted with H₂S.

To determine which of the given compounds will produce a metal sulfide when reacted with hydrogen sulfide (H₂S), we need to analyze each option provided. ### Step-by-step Solution: 1. **Identify the Compounds**: The options given are: - A) COCl₂ - B) Cd(CN)₄²⁻ - C) Zn(OH)₂²⁻ ...
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