Home
Class 12
MATHS
A and B play a game in which they altern...

`A` and `B` play a game in which they alternately call out positive integers less than or equal to `n`, according to the following rules. A goes first and always call out an odd number, `B` always calls out an even number each playerr must call out a number which is greater than the previous number (except for `A's` first turn). The game ends when one player cannot cal out a number, then which of the following is/are correct?

A

For `n=6`, number of possible games is 8

B

For `n=6`, number of possible games is 10

C

For `n=10`, number of possible games is 55

D

For `n=8` number of possible games is 21

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the game played by players A and B. Here’s a step-by-step solution: ### Step 1: Understand the Game Rules - Player A starts and can only call out odd numbers. - Player B can only call out even numbers. - Each player must call out a number greater than the previous number called (except for A's first turn). - The game ends when a player cannot call out a valid number. ### Step 2: Identify the Range of Numbers - Both players can only call out numbers from 1 to n. - A can call odd numbers: 1, 3, 5, ..., up to the largest odd number ≤ n. - B can call even numbers: 2, 4, 6, ..., up to the largest even number ≤ n. ### Step 3: Determine the Possible Moves - If n is odd, A can call odd numbers up to n, and B can call even numbers up to n-1. - If n is even, A can call odd numbers up to n-1, and B can call even numbers up to n. ### Step 4: Count the Possible Games Let’s denote the number of possible games for a given n as P(n). We can derive P(n) based on previous values: 1. **Base Cases:** - P(1) = 1 (A calls 1, B cannot call anything) - P(2) = 1 (A calls 1, B calls 2) - P(3) = 2 (A can call 1 or 3, B can only call 2) - P(4) = 3 (A can call 1, 3; B can call 2, 4) - P(5) = 5 (A can call 1, 3, 5; B can call 2, 4) - P(6) = 8 (A can call 1, 3, 5; B can call 2, 4, 6) 2. **Recursive Relation:** - For n ≥ 2, we can express P(n) as: \[ P(n) = P(n-1) + P(n-2) \] This is because: - If A calls an odd number (1, 3, ..., n-1), then B has the remaining options. - If A calls the largest odd number (n), then B has no options left. ### Step 5: Calculate P(n) for Specific Values Using the recursive relation, we can calculate P(n) for various values of n: - P(7) = P(6) + P(5) = 8 + 5 = 13 - P(8) = P(7) + P(6) = 13 + 8 = 21 - P(9) = P(8) + P(7) = 21 + 13 = 34 - P(10) = P(9) + P(8) = 34 + 21 = 55 ### Step 6: Verify the Options Now we can check which options are correct based on the calculated values: - For n = 6, P(6) = 8 (Correct) - For n = 8, P(8) = 21 (Correct) - For n = 10, P(10) = 55 (Correct) - For n = 2, P(2) = 1 (Incorrect if stated otherwise) ### Conclusion The correct options based on the values calculated are: - A (n = 6, P(6) = 8) - C (n = 8, P(8) = 21) - D (n = 10, P(10) = 55)

To solve the problem, we need to analyze the game played by players A and B. Here’s a step-by-step solution: ### Step 1: Understand the Game Rules - Player A starts and can only call out odd numbers. - Player B can only call out even numbers. - Each player must call out a number greater than the previous number called (except for A's first turn). - The game ends when a player cannot call out a valid number. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Which of the following is the odd one out ?

Which of the following is the odd one out ?

Is the LCM of two numbers always greater than the two numbers ?

Find odd one out, according to parasitism.

Prove that a positive integer n is prime number, if no prime p less than or equal to sqrtn divides n.

State if the result is always odd or always even: Two even numbers are added.

State if the result is always odd or always even: Two consecutive numbers are multiplied

Which one of the following must be greater than x, if x is real number?

State if the result is always odd or always even: Three odd numbers are added

State if the result is always odd or always even: One even and two odd numbers are added