Home
Class 12
PHYSICS
Two parallel large metal plates, each of...

Two parallel large metal plates, each of area `A` are piaced at a distance `d` apart. Light of intensity `I` and wavelength `lambda` falls on the plate `1` which is photosensitive. The efficiency of photoelectron emission is `100%`. The photoelectrons are immediately swept away from plate `1` in such a way that the plate `2` remains neutral. Find the potential difference between the two plates at any time `t`, if plate `1` is neutral initially.

Text Solution

Verified by Experts

`N=(lambdaIAt)/(hc)`, where `N` is number of photons falling on the plate.
`Q_(1)=(lambdaIAt)/(hc)e`, `v_(1)-v_(2)=(Q//2)/(C )`, where `C=(epsilon_(0)A)/(d)`
`V_(1)-V_(2)=(lambdaIAte)/(2hcepsilon_(0)A)d=(lambdaIdte)/(2hcepsilon_(0))`
Promotional Banner

Similar Questions

Explore conceptually related problems

In a parallel plate capacitor of capacitor 1muF two plates are given charges 2muC and 4muC the potential difference between the plates of the capacitor is

Four parallel large plates separated by equal distance d are arranged as shown in. The area of the plates is S Find the potential differnce between plats B and C if plate B is given a charge Q. .

A parallel plate capacitor is charged. If the plates are pulled apart

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

Two parallel conducting plates of area A each,are placed at distance d.A third plate ,identical with the first two placed at a distance d/3 from one of the plate as shown in figure.The capacitance of given arrangement is

Charges 2q and -3q are given to two identical metal plates of area of cross section A . the distance between the plates is d . Find the capacitance and potential difference between the plates.

Two parallel conducting plates of a capacitor of capacitance C containing charges Q and -2Q at a distance d apart. Find out potential difference between the plates of capacitors.

Two plates are 2cm apart, a potential difference of 10 volt is applied between them, the electric field between the plates is

A charge of 1 muC is given to one plate of a parallel - plate capacitor of capacitance 0.1muF and a charge of 2 muC is given to the other plate . Find the potential difference developed between the plate .

An electron having charge e and mass m starts from the lower plate of two metallic plates separated by a distance d . If the potential difference between the plates is V , the time taken by the electron to reach the upper plate is given by .