Two soap bubbles of equal radii (`R=8cm`) are stuck together with an intermediate film separating them. Surface tension of solution forming bubbles is `7xx10^(-3)Newton//meter`. What will be distance between the centers of soap bubbles (in cm).

The surface tension of a soap solution is 30 xx 10^(-3) N m^(-1) . How much work is done to increase the radius of a soap bubble from 2 cm to 3 cm?

If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be

The surface tension of a soap solution is 30 xx 10^(-3) N m^(-1) . How much work is done to increase the radius of a soap bubble from 1.5 cm to 3 cm?

The surface tension of a soap solution is 2xx10^(-2) N//m . To blow a bubble of radius 1cm, the work done is

Two soap bubbles are stuck together with an intermediate film separating them. Compute the radius of curvature of this film given that the radii of the bubbles in this arrangement are r_(1) and r_(2) respectively. If r_(1) gt r_(2) state clearly which way the intermediate film will bulge. For the case when r_(1)=r_(2)=2cm calculate he radius of the bubble formed by bursting the intermediate film. The volume of a spherical dome of radius R and height h is pib^(2)(3R-b)//3 .

surface tension of soap solution is 4*10^(-2) N/m . If a soap bubble of radius 5 cm is blown, then the amount of work done is

Two soap bubbles of radii 2 cm and 4 cm join to form a double bubble in air, then radius of. curvature of interface is

Two soap bubbles of radii 2 cm and 3 cm are brought in contact. Find the radius of curvature (in cm) of the contact surface.

A soap bubble of radius 3cm is chaged with 9 nC (nanocoulomb) Find the excess pressure inside the bubble surface tension of soap solution = 3×10^(-3) m^(-1)

Two soap bubbles of radii a and b coalesce to form a single bubble of radius c . If the external pressure is P , find the surface tension of the soap solution.