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In a Coolidge tube, the potential differ...

In a Coolidge tube, the potential difference used to aceleerate the electrons is increased from `12.4 ` kV to `24,8 kV` As a result the difference between the wavelength of `k_(alpha)` line and minimum wavelength increases to thrice its former value. The wavelength of the `k_(alpha) ` line is `((hc)/(e)=12.4 kVÅ)`

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According to question
`3(lambda_(K_(alpha))-(12.4)/(12.4))=lambda_(K_(alpha))-(12.4)/(12.4)`
`rArr lambda_(K_(alpha)=1.25A^(@)`
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