`S_(1)` and `S_(2)` are two equally intense coherent point second sources vibrating in phase. The resultant intensity at `P_(1)` is `80 SI` units then resultant intensity at `P_(2)` in `SI` units will be

N. m^(-1) is the S.I unit of

Two incoherent sources of intensities l and 4l superpose then the resultant intensity is

S.I unit of Electric intensity is

The SI unit of electric field intensity is

Consider two coherent, monochromatic (wavelength lambda ) sources S_(1) and S_(2) , separated by a distance d. The ratio of intensities of S_(1) and that of S_(2) (which is responsible for interference at point P, where detector is located) is 4. The distance of point P from S_(1) is (if the resultant intensity at point P is equal to (9)/(4) times of intensity of S_(1) ) ("Given : "angleS_(2)S_(1)P=90^(@), d gt0 and n" is a positive integer")

Two incoherent sources of light emitting light of intensity I_(0) and 3I_(0) interfere in a medium. Calculate, the resultant intensity at any point.

When two waves of intensities l_1 and l_2 coming from coherent sources interfere at a point P, where phase difference is phi , then resultant intensity (l_(res)) at point P would be

If two sources have a randomly varying phase difference f(t), the resultant intensity will be given by:

Two identical sounds s_(1) and s_(2) reach at a point P phase. The resultant loudness at a point P is not higher than the loudness of s_(1) . The value of n is

Two sinusoidal waves of intensity I having same frequency and same amplitude interferes constructively at a point. The resultant intensity at a point will be