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A solid hemispherical uniformly charged ...

A solid hemispherical uniformly charged body having charge `Q` is kept symmetrically along the `y`-axis as shown in the figure. The net electric field at (`d`, `0`,`0`) is

A

`(1)/(4piepsilon_(0))(Q)/(d^(2))`

B

less then `(1)/(4piepsilon_(0))(Q)/(d^(2))`

C

` gt (1)/(4piepsilon_(0))(Q)/(d^(2))` and `lt (1)/(4piepsilon_(0))(2Q)/(d^(2))`

D

`(1)/(4piepsilon_(0))(2Q)/(d^(2))`

Text Solution

Verified by Experts

Due to solid hemispherical charge of `2Q` the field will be `(1)/(4piepsilon_(0))xx(2Q)/(d^(2))` along `x-`axis. So due to one hemisphere the component of field along `x-` direction will be `(1)/(4piepsilon_(0))xx(Q)/(d^(2))` . And hence the net field will be more than `(1)/(4piepsilon_(0))xx(2Q)/(d^(2))`
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