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A force vecF=(3xy-5z)hatj+4zhatk is appl...

A force `vecF=(3xy-5z)hatj+4zhatk` is applied on a particle. The work done by the force when the particle moves from point `(0, 0, 0)` to point `(2, 4, 0)` as shown in figure.

A

`(280)/(5)`

B

`(140)/(5)`

C

`(232)/(5)`

D

`(192)/(5)`

Text Solution

Verified by Experts

The `z`-component of the force and the `x`-component of displacement are ieffective here.
`dW=F_(y)dy=3xy.dy` (`:'z=0`)
`=6x^(4)dx` (`:'y=x^(2)` )
Integrating between `x=0` and `x=2` gives the result.
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