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A block of mass sqrt(3)//10kg is placed ...

A block of mass `sqrt(3)//10kg` is placed on a rough horizontal surface as shown in the figure. A force of 1N is applied at one end of the block and the block remains stationary. The normal force exerted by the sruface on the block acts(g=10`m//s^(2)`)

A

through the centre of mass of the block

B

through point `A`.

C

through point `B`.

D

through the point at a distance `5cm`. From `A`.

Text Solution

Verified by Experts

For equilibrium
`sumvecF=0 sumvectau=0`
`N=(sqrt(3))/(2)-(1)/(2)`……..(`1`)
Torque about `A` due to all forces excluding normal face is found to be zero.
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