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A circular conducting loop of radius R c...

A circular conducting loop of radius `R` carries a current `I`. Another straight infinite conductor carrying current `I` passes through the diameter of this loop as shown in the figure. The magnitude of force exerted by the straight conductor on the loop is

A

`pimu_(0)I^(2)`

B

`mu_(0)I^(2)`

C

`(mu_(0)I^(2))/(2pi)`

D

`(mu_(0)I^(2))/(pi)`

Text Solution

Verified by Experts

`dF=((mu_(0)I)/(2piRsintheta)).(Ird theta)`
`rArr "Total force" F=intdF sin theta`
`=int_(0)^(2pi)(mu_(0)I^(2))/(2pi)d theta=mu_(0)I^(2)`
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