Home
Class 12
PHYSICS
Two vertical plates submerged partially ...

Two vertical plates submerged partially in a wetting liquid form a wedge with a very small angle `delta varphi`. The edge of this wedge is vertical. The density of the liquid is `rho`, its surface tension is `alpha`, the contact angle is `theta`. Find the height `h`, to which the liquid rises, as a function of the distance `x` from the edge.

A

`(2T)/(rho gx(deltatheta))`

B

`(2T)/(rho gx)`

C

`(2T(deltatheta))/(rho gx)`

D

`(T)/(rho gx(deltatheta))`

Text Solution

AI Generated Solution

To solve the problem of finding the height \( h \) to which the liquid rises as a function of the distance \( x \) from the edge of the wedge formed by two vertical plates submerged in a wetting liquid, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Geometry**: - We have two vertical plates forming a wedge with a very small angle \( \delta \varphi \). - The liquid will rise to a height \( h \) due to the effects of surface tension and gravity. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

When a vertical capillary of length l with a sealed upper end was brought in contact with the surface of a liquid, the level of this liquid rose to the height h . The liquid density is rho , the inside diameter the capillary is d , the contact angle is theta , the atmospheric pressure is rho_(0) . Find the surface tension of the liquid. (Temperature in this process remains constant.)

When a vertical capillary of length with the sealed upper end was brought in contact with the surface of a liquid, the level of this liquid rose to the height h . The liquid density is rho , the inside diameter the capillary is d , the contact angle is theta , the atmospheric pressure is rho_(0) . Find the surface tension of the liquid. (Temperature this process remains constant.)

Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', Surface tension is T and angle of contact is theta then rise of liquid between the plates due to capillary will be

A liquid is coming out from a vertical tube. The relation between the weight of the drop W , surface tension of the liquid T and radius of the tube r is given by, if the angle of contact is zero

Find value of surface tension if contact angle is 0 and after lowering tube height of liquid is 15 cm and radius is 0.015 cm (density = 900 kg/ (m^3) ) (g = 10 m/ (s^2)

A capillary tube with inner cross-section in the form of a square of side a is dipped vertically in a liquid of density rho and surface tension rho which wet the surface of capillary tube with angle of contact theta . The approximate height to which liquid will be raised in the tube is : (Neglect the effect of surface tension at the corners of capillary tube)

A liquid of density rho and surface tension sigma rises in a capillary tube of diameter d. Angle of contact between the tube and liquid is zero. The weight of the liquid in the capillary tube is:

A stream of liquid, set at an angle theta , is directed against a plane surface (figure). The liquid, after hitting the surface, spreads over it. Find the pressure on the surface. The density of the liquid is rho and its velocity is v.

A student writes the equation for the capillary rise of a liquid in a tube as h=(rhog)/(2Tcos theta) , where r is the radius of the capillary tube, rho is the density of liquid, T is the surface tension and theta is the angle of contact. Check the correctness of the equation using dimensional analysis?

A closed tube in the form of an equilateral triangle of side l contains equal volumes of three liquids which do not mix and is placed vertically with its lowest side horizonta. Find 'x' in the figure if the densities of the liquids are in A.P .