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A particle is projected from point P on ...

A particle is projected from point `P` on inclined plane `OA` perpendicular to it with certain velocity `v`. It hits another inclined plane `OB` at point `Q` perpendicular to it. Point `P` and `Q` are at `h_(1)` and `h_(2)` height from ground. `(alpha gt beta)`

A

`h_(1)=h_(2)`

B

`h_(1) gt h_(2)`

C

`h_(1) lt h_(2)`

D

any of above depends on speed of projection.

Text Solution

Verified by Experts

perpendicular to `OB`, `v'=-vsintheta(90^(@)-alpha-beta)+g cos beta t`…..(`i`)
Parallel to `OB`, `0=v cos(90^(@)-alpha-beta)-g sin beta t`……(`ii`)
on solving `v'=(vsin alpha)/(sinbeta)`
for `alpha gt beta`, `v' gt v`, so by energy conservation `h_(2) lt h_(1)`
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