A block of wood is floating in water such that `1//2` of it is submerged in water when the same block is floated in alcohol, `1//3^(rd)` of it's volume is submerged Now a mixture of water and alcohol is made taking equal volume of both and block is floated in it. What is the % of it's volume that is now submerged?

Options

A. `50`
B. `40`
C. `25`
D. `60`

Explanation

To solve the problem step by step, we can follow these calculations:

### Step 1: Understand the problem
A block of wood is floating in two different liquids: water and alcohol. We know how much of the block is submerged in each liquid. We need to find out how much of the block is submerged when it is placed in a mixture of both liquids.

### Step 2: Define variables
Let:
- \( V_0 \) = Volume of the wooden block
...