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A rod of mass m and length l is rotating...

A rod of mass `m` and length `l` is rotating about a fixed point in the ceiling with an angular velocity `omega` as shown in the figure. The rod maintains a constant angle `theta` with the vertical.
What is the rate of change of angular momentum of the rod ?

A

`(momega^(2)l^(2)sintheta)/(6)`

B

`(momega^(2)l^(2)sin2theta)/(6)`

C

`(momega^(2)l^(2)sin^(2)theta)/(6)`

D

`(momega^(2)l^(2)cos^(2)theta)/(6)`

Text Solution

Verified by Experts

The vertical component of the angular momentum remains constant while its horizontal component keeps changing the direction.
`dL=(momegalsin(2theta))/(6)xxomegadtrArr(dL)/(dt)=(momega^(2)l^(2))/(6)sin(20)`
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