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When a particle is projected at some ang...

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains `g` in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path
Consider that a particle is projected with velocity `u=10 m//s` at an angle `theta=60^(@)` with the horizontal and take value of `g=10m//s^(2)`. Now answer the following questions.
The radius of curvature of path of particle at the instant when the velocity vector of the particle becomes perpendicular to initial velocity vector is

A

`(20)/(3sqrt(3))m`

B

`(10)/(3sqrt(3))m`

C

`(40)/(3sqrt(3))m`

D

`(80)/(3sqrt(3))m`

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