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In the region between the plane z=0 and ...

In the region between the plane `z=0` and `z=a (a gt 0)`, the uniform electric and magnetic fields are given by `vecE=E_(0)(hatk-hatj)`, `vecB=B_(0)hati`. The region defined by `a le z le b` contains only magnetic field `vecB= -B_(0)hati`. Beyond `z gt b` no field exits. A positive point charge `q` is projected from the origin with velocity `v_(0)hatk`. Assuming the mass of the particle to be `(2)/(3)(qE_(0)a)/(v_(0)^(2))`.
The minimum value of `b` such that the particle reverses its direction completely is

A

`(4E_(0)a)/(3v_(0)B_(0))`

B

`a(1+(4E_(0))/(3v_(0)B_(0)))`

C

`(2E_(0)a)/(3v_(0)B_(0))`

D

`a(1+(2E_(0))/(3v_(0)B_(0)))`

Text Solution

Verified by Experts

`(b-a)` is the radius of the circle
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