Home
Class 12
PHYSICS
A thin wire is wound very tightly in one...

A thin wire is wound very tightly in one layer on the surface of a sphere of paramagnetic material `(mu_(r)~~1)`. The planes of all the turns can be assumed to be perpendicular to the same diameter of the sphere. The turns over the entire surface of the sphere. The radius of the sphere is `R`, the total number of turns is `N`, and the current in the winding is `I`. Find the magnetic induction at the centre of the sphere. (Given `mu_(0)NI=20R`)

Text Solution

AI Generated Solution

To solve the problem of finding the magnetic induction at the center of a sphere wound with a thin wire, we can follow these steps: ### Step 1: Understand the Geometry We have a sphere of radius \( R \) with a thin wire wound tightly around it in one layer. The wire creates \( N \) turns, and the current flowing through the wire is \( I \). The planes of the wire turns are perpendicular to a diameter of the sphere. **Hint:** Visualize the sphere and the wire wrapped around it. Recognize that the wire creates a magnetic field due to the current flowing through it. ### Step 2: Determine the Magnetic Field Contribution from a Ring ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Flux passing through the shaded surface of a sphere when a point charge q is placed at the center is (radius of the sphere is R)

Find the moment of inertia of a sphere about a tangent to the sphere, while the mass of the sphere is M and the radius of the sphere is R.

Find the moment of inertia of a sphere about a tangent to the sphere, while the mass of the sphere is M and the radius of the sphere is R.

Which of the following is the ratio of the surface area of the sphere with radius r to its volume?

For a sphere made out of a certain material, the moment of inertia of the sphere is proportional to [ radius of the sphere = R ]

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

(i) The numberical value of the volume and surface of a sphere are equal. Find the diameter of the sphere. (ii) The curved surved surface of a sphere is equal to the area of a circle of radius 2.8 cm. Find the volume of the sphere.

The ratio of the surface area of sphere A to the surface area of sphere B is 729 : 1. What is ratio of the volume of sphere A to sphere B ?

Find the ratio of the total surface area of a sphere and a hemisphere of same radius.

A sphere has a volume of 36pi . What is the surface area of the sphere? (Ther surface area of a sphere is given by the formula A=4pi r^2 )