Two particles `A` and `B` are situated at point `(60,0)` at `t=0`. The particle `A` move on a circle given by `X^(2)+Y^(2)=3600` and with a speed `6 pi m//s`, while `B` moves with a constant velocity.
Find the velocity of `B` so that the collision takes places between `A` and `B` at point `(60,0)`.

Explanation

To solve the problem, we need to find the velocity of particle B such that it collides with particle A at the point (60, 0). Let's break down the solution step by step.

### Step 1: Understand the motion of particle A
Particle A moves on a circle defined by the equation \(x^2 + y^2 = 3600\). The radius of this circle is 60 meters (since \(60^2 = 3600\)). Particle A starts at the point (0, 60) and moves with a speed of \(6\pi\) m/s.

### Step 2: Determine the distance A travels to reach (60, 0)
To find the distance that particle A travels to reach the point (60, 0), we need to calculate the arc length from (0, 60) to (60, 0) on the circle. The angle subtended by this arc at the center of the circle can be calculated as follows:

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