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A particle of mass 3m is dropped from ce...

A particle of mass `3m` is dropped from certain height at `t=0` at time `t=t_(0)`. The particle explodes and breaks into two parts `m` and `2m`. At time `t=3t_(0)` velocity of lighter mass is `vecV=V_(1)hati+V_(2)hatj`. The velocity of heavier mass at `t=t_(0)` (just after explosion) is (if `y` represents vertical and `x` represents horizontal)

A

`-V_(1)hati-V_(2)hatj`

B

`-(V_(1))/(2)hati+((-V_(2)+5"gt"_(0)))/(2)hatj`

C

`-(V_(1))/(2)hati+((-V_(2)+5"gt"_(0))hatj)/(2)`

D

none of the above

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