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Two blocks of masses of 0.2 kg and 0.5 k...

Two blocks of masses of `0.2 kg` and `0.5 kg` which are placed `22m` apart on a horizontal surface `(mu = 0.5)` are acted uponby two forces of magnitude `3 N`each as shown in figure in time `t = 0` Then the time t at which they collide with each other is

A

`1sec`

B

`sqrt(2)sec`

C

`2sec`

D

none of these

Text Solution

Verified by Experts

`a_(1)=(F-f_(1))/(m_(1))=(F-mum_(1)g)/(m_(1))=10m//s^(2)`
`a_(2)=(-F+mum_(2)g)/(m_(2))= -1m//s^(2)`
`:. S=(1)/(2)a_(real)t^(2)`
`22=(1)/(2)[10-(-1)]t^(2)rArrt=2sec`
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