A particle `m` starts with zero velocity along a line `y=4d`. The position of particle `m` varies as `x=A sin omegat`, At `omegat=pi//2`, its angular momentum with respect to the origin

Options

A. `mAomegad`
B. `momegad//A`
C. `mAd//omega`
D. zero

Explanation

To solve the problem, we need to find the angular momentum of a particle `m` at the moment when `omega t = pi/2`. The particle's position varies as `x = A sin(omega t)`, and it starts with zero velocity along the line `y = 4d`.

### Step-by-Step Solution:

1. **Understand the Position Function:**
The position of the particle is given by:
\[
x = A \sin(\omega t)
...