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An air bubble of radius 5mm rises throug...

An air bubble of radius `5mm` rises through a vat of syrup at a steady speed `4mm//s`. If the syrup has a density of `1.4xx10^(3)kg//m^(3)`, what is its viscocity ?

A

`1.15 kg//m-s`

B

`15 kg//m-s`

C

`2.25 kg//m-s`

D

`19.05 kg//m-s`

Text Solution

AI Generated Solution

To find the viscosity of the syrup through which the air bubble rises, we can use the formula for terminal velocity of a sphere moving through a viscous fluid. The terminal velocity \( V_t \) is given by: \[ V_t = \frac{2}{9} \frac{r^2 (\rho - \sigma)}{\eta g} \] Where: - \( r \) is the radius of the bubble, ...
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