The period of a particle executing SHM is `T`. There is a point `P` at a distance `'x'` from the mean position `'O'`. When the particle passes `P` towards `OP`, it has speed `v`. Find the time in which it returns to `P` again.

Explanation

To find the time in which a particle executing Simple Harmonic Motion (SHM) returns to point P after passing it, we can follow these steps:

### Step 1: Understand the SHM motion
The particle is executing SHM with a period \( T \). The position of the particle at any time \( t \) can be described by the equation:
\[ x(t) = A \sin(\omega t) \]
where \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( \omega = \frac{2\pi}{T} \).
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