A pendulum has time period `T` in air when it is made to oscillate in water it acquired a time period `T = sqrt(2)T` The density of the pendulum bob is equal to (density) of water `= 1)`

Options

A. `sqrt(2)`
B. `2`
C. `2sqrt(2)`
D. None of these

Explanation

To solve the problem, we need to analyze the relationship between the time period of a pendulum in air and when it is submerged in water, and how this relates to the density of the pendulum bob.

### Step-by-Step Solution:

1. **Understanding the Time Period of a Pendulum:**
The time period \( T \) of a simple pendulum in air is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g}}
...