A spring is loaded with two blocks `m_(1)` and `m_(2)` where `m_(1)` is rigidly fixed with the spring and `m_(2)` is just kept on the block `m_(1)`. The maximum energy of oscillation is possible for the system having the block `m_(2)` in constant with `m_(1)` is

Options

A. `(m_(1)^(2)g^(2))/(2k)`
B. `(m_(2)^(2)g^(2))/(2k)`
C. `((m_(1)+m_(2))^(2)g^(2))/(2k)`
D. None of these

Explanation

To find the maximum energy of oscillation for the system with blocks \( m_1 \) and \( m_2 \), we can follow these steps:

### Step 1: Understanding the System
We have a spring with a block \( m_1 \) rigidly fixed to it, and another block \( m_2 \) resting on top of \( m_1 \). The total mass of the system is \( m_1 + m_2 \).

### Step 2: Formula for Maximum Energy
The maximum energy of oscillation \( E \) in a spring-mass system is given by the formula:
\[
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