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Shown in the figure is an R-L circuit. J...

Shown in the figure is an `R-L` circuit. Just after the key `(K)` is closed

A

the current in the circuit is zero

B

potential drop across the resistor is zero

C

emf developed across the inductor equals the emf of the battery

D

no heat is dissipated in the circuit

Text Solution

Verified by Experts

If the equilibrium current in the circuit is `i_(0)`, current at any time in transient state is given as
`i=i_(0)(1-e^(-(t)/(tau)))` where `tau=(L)/(R )`
Putting `t=0`, `i=0`
`rArr ` The voltage drop across the inductor is `E'` that oppose the applied emf `E`
`rArr E'=E` numerically.
Since the circuit current is zero, the heat loss that is proportional to `i_(0)^(2)R` will be zero
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