Find the centre and the radius of the circles
`2x^(2) + lambda xy + 2y^(2) + (lambda - 4) x+6y - 5 = 0`, for some `lambda`

Find the centre and radius of the the circles: x^2 +y^2 - 4x-6y-14=0

Find the centre and radius of the circle 3x^(2)+ 3y^(2) - 6x + 4y - 4 = 0

Find the centre and radius of the circle x^(2) + y^(2) - 6x + 4y - 12 =0 .

Find the centre and radius of each of the following circle: x^2+y^2-4x+6y=5

Centre and Radius of circle 2x^(2)+2y^(2)+5x+6y+3=0

Find the radius and centre of the circle of the circle x^(2) + y^(2) + 2x + 4y -1=0 .

The coordinates of the centre and radius of the circle represented by the equation (3-2lambda)x^(2)+lambda y^(2)-4x+2y-4=0 are

The line 4y - 3x + lambda =0 touches the circle x^2 + y^2 - 4x - 8y - 5 = 0 then lambda=

If the common chord of the circles x^(2) + ( y -lambda)^(2) =16 and x^(2) +y^(2) =16 subtend a right angle at the origin then ' lambda' is equal to :

The centre of family of circles cutting the family of circles x^2 + y^2 + 4x(lambda-3/2) + 3y(lambda-4/3)-6(lambda+2)=0 orthogonally, lies on