Home
Class 12
MATHS
If 4l^2 - 5m^2 + 6l+1=0, then show that ...

If `4l^2 - 5m^2 + 6l+1=0`, then show that the line `lx+my+1=0` touches a fixed circle. Find the centre and radius of the circle.

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

If 4l^2-5m^2+6l+1=0. Prove that lx+my+1=0 touches a definite circle. Find the centre & radius of the circle.

A line is tangent to a circle if the length of perpendicular from the centre of the circle to the line is equal to the radius of the circle. If 4l^2 - 5m^2 + 6l + 1 = 0 , then the line lx + my + 1=0 touches a fixed circle whose centre. (A) Lies on x-axis (B) lies on yl-axis (C) is origin (D) none of these

A line is tangent to a circle if the length of perpendicular from the centre of the circle to the line is equal to the radius of the circle. If 4l^2 - 5m^2 + 6l + 1 = 0 , then the line lx + my + 1=0 touches a fixed circle whose centre. (A) Lies on x-axis (B) lies on yl-axis (C) is origin (D) none of these

If 8l^2+35 m^2+36 l m+6l+12 m+1=0 and the line l x+m y+1=0 touches a fixed circle whose centre is (alpha,beta) and radius is ' r^(prime), then the value of (alpha+beta-r) is equal to

A circle centre (1,2) touches y-axis. Radius of the circle is

If the line l x+m y-1=0 touches the circle x^2+y^2=a^2 , then prove that (l , m) lies on a circle.

If the line l x+m y-1=0 touches the circle x^2+y^2=a^2 , then prove that (l , m) lies on a circle.

Consider the relation 4l^(2)-5m^(2)+6l+1=0 , where l, m inR . The line lx+my+1=0 touches a fixed circle whose equation is

Show that the line lx+my+n=0 is a normal to the circles S=0 iff gl+mf=n .

Show that the line (x-2)costheta+(y-2)sintheta=1 touches a circle for all values of theta .Find the circle.