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a square is inscribed in the circle x^2 ...

a square is inscribed in the circle `x^2 + y^2- 10x - 6y + 30 = 0.` One side of the square is parallel to `y = x + 3,` then one vertex of the square is :

A

(3,3)

B

(7,3)

C

`(6,3-sqrt3)`

D

`6,3+sqrt3)`

Text Solution

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The correct Answer is:
A, B
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