`5x ^2+17xy−12y ^2`

Find the real numbers (x,y) that satisfy the equation: xy^(2) = 15x^(2) +17xy + 15y^(2) x^(2)y = 20x^(2) + 3y^(2)

Divide : 12x^(2) + 7xy - 12y^(2) by 3x + 4y

Subtract using horizontal method : 5x^(2) + 7xy - 2y^(2) " from " 3x^(2) + 5xy + 2y^(2)

Factorise : (iv) 5x^(2) - 4xy - 12y^(2)

If lambdax^(2)-10xy+12y^(2)+5x-16y-3=0 , represents a pair of straight lines, then the value of lambda is

If first degree terms and constant term are to be removed from the equation 12x^(2)+7xy-12y^(2)-17x-31y-7=0 , then the origin must be shifted at shifted at the point .

Find the new equation of curve 12x^2+7xy-12y^2-17x-31y-7=0 after removing the first degree terms.

The value of lambda with |lambda| lt 16 such that 2x^(2) - 10xy +12y^(2) +5x +lambda y - 3 = 0 represents a pair of straight lines is

Consider the equation of a pair of straight lines as 2x^(2)-10xy+12y^(2)+5x-16y-3=0 . The angles between the lines is theta . Then the value of tan theta is

Consider the equation of a pair of straight lines as 2x^(2)-10xy+12y^(2)+5x-16y-3=0 . The point of intersection of lines is (alpha, beta) . Then the value of alpha beta is (a) 35 (b) 45 (c) 20 (d) 15