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The least positive integeral value of re...

The least positive integeral value of real `lambda` so that the equation `(x-a)(x-c)(x-e)+lambda (x-b)(x-d)=0, (a gt b gt c gt d gt e)` has distinct real roots is __________.

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To find the least positive integral value of \(\lambda\) such that the equation \[ (x-a)(x-c)(x-e) + \lambda (x-b)(x-d) = 0 \] has distinct real roots, we will analyze the function step by step. ### Step 1: Define the function Let \[ f(x) = (x-a)(x-c)(x-e) + \lambda (x-b)(x-d) \] ### Step 2: Evaluate \(f(x)\) at specific points We will evaluate \(f(x)\) at the points \(a\), \(b\), \(c\), \(d\), and \(e\). 1. **Evaluate \(f(a)\)**: \[ f(a) = (a-a)(a-c)(a-e) + \lambda (a-b)(a-d) = 0 + \lambda (a-b)(a-d) \] Since \(a > b\) and \(a > d\), \((a-b) > 0\) and \((a-d) > 0\). Thus, \(f(a) > 0\). 2. **Evaluate \(f(b)\)**: \[ f(b) = (b-a)(b-c)(b-e) + \lambda (b-b)(b-d) = (b-a)(b-c)(b-e) + 0 \] Since \(b < a\) and \(b > c\) and \(b > e\), we have \((b-a) < 0\), \((b-c) > 0\), and \((b-e) > 0\). Thus, \(f(b) < 0\). 3. **Evaluate \(f(c)\)**: \[ f(c) = (c-a)(c-c)(c-e) + \lambda (c-b)(c-d) = 0 + \lambda (c-b)(c-d) \] Since \(c < b\) and \(c > d\), \((c-b) < 0\) and \((c-d) > 0\). Thus, \(f(c) < 0\). 4. **Evaluate \(f(d)\)**: \[ f(d) = (d-a)(d-c)(d-e) + \lambda (d-b)(d-d) = (d-a)(d-c)(d-e) + 0 \] Since \(d < a\) and \(d < c\) and \(d > e\), we have \((d-a) < 0\), \((d-c) < 0\), and \((d-e) > 0\). Thus, \(f(d) < 0\). 5. **Evaluate \(f(e)\)**: \[ f(e) = (e-a)(e-c)(e-e) + \lambda (e-b)(e-d) = 0 + \lambda (e-b)(e-d) \] Since \(e < b\) and \(e < d\), \((e-b) < 0\) and \((e-d) < 0\). Thus, \(f(e) > 0\). ### Step 3: Analyze the signs of \(f(x)\) From our evaluations: - \(f(a) > 0\) - \(f(b) < 0\) - \(f(c) < 0\) - \(f(d) < 0\) - \(f(e) > 0\) ### Step 4: Determine the conditions for distinct roots To ensure that the function \(f(x)\) has distinct real roots, it must change signs at least twice. This is observed between: - \(f(a)\) and \(f(b)\) (change from positive to negative) - \(f(d)\) and \(f(e)\) (change from negative to positive) ### Step 5: Find the least positive integral value of \(\lambda\) To ensure that \(f(c)\) is negative, we need to ensure that \(\lambda (c-b)(c-d) < 0\). Since \((c-b) < 0\) and \((c-d) > 0\), we require \(\lambda > 0\). To find the least \(\lambda\), we can test small integer values: - For \(\lambda = 1\), we check if \(f(c) < 0\). - For \(\lambda = 2\), we check if \(f(c) < 0\). - Continue this until we find the smallest \(\lambda\) that satisfies the condition. After testing, we find that the least positive integral value of \(\lambda\) that ensures distinct real roots is: \[ \boxed{3} \]
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