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Find the domain and the range of the fun...

Find the domain and the range of the function `y=f(x)`, where `f(x)` is given by
`tanx`

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The correct Answer is:
To find the domain and range of the function \( y = f(x) \), where \( f(x) = \tan x \), we can follow these steps: ### Step 1: Understanding the function The function \( f(x) = \tan x \) is defined as the ratio of the sine and cosine functions: \[ \tan x = \frac{\sin x}{\cos x} \] This means that \( \tan x \) is undefined wherever \( \cos x = 0 \). ### Step 2: Finding the points where \( \tan x \) is undefined The cosine function is zero at the following points: \[ x = \frac{\pi}{2} + n\pi \quad \text{for } n \in \mathbb{Z} \] This means that \( \tan x \) is undefined at: - \( x = \frac{\pi}{2}, \frac{3\pi}{2}, -\frac{\pi}{2}, -\frac{3\pi}{2}, \ldots \) ### Step 3: Determining the domain Since \( \tan x \) is undefined at these points, the domain of \( f(x) \) includes all real numbers except these points. In interval notation, the domain can be expressed as: \[ \text{Domain} = \mathbb{R} \setminus \left\{ \frac{\pi}{2} + n\pi \mid n \in \mathbb{Z} \right\} \] This means the domain consists of all real numbers except for the points where \( \tan x \) is undefined. ### Step 4: Analyzing the range The function \( \tan x \) can take any real value as \( x \) approaches the points where it is undefined. As \( x \) approaches \( \frac{\pi}{2} \) from the left, \( \tan x \) approaches \( +\infty \), and as \( x \) approaches \( \frac{\pi}{2} \) from the right, \( \tan x \) approaches \( -\infty \). This behavior repeats for every interval of \( \pi \). ### Step 5: Determining the range Since \( \tan x \) can take any value from \( -\infty \) to \( +\infty \), the range of \( f(x) \) is: \[ \text{Range} = \mathbb{R} \] ### Final Answer - **Domain**: \( \mathbb{R} \setminus \left\{ \frac{\pi}{2} + n\pi \mid n \in \mathbb{Z} \right\} \) - **Range**: \( \mathbb{R} \)
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