If `A={2}`, `B={5}`, `C={3,4,6}`, then verify that `Axx(BnnC)=(AxxB)nn(AxxC)`.

Axx(B-C)=(AxxB)-(BxxC)

If A={1,2,3},B={4},C={5}, then verify that: Axx(BuuC)=(AxxB)uu(AxxC)

If A={1,4},B={2,3,6} and C={2,3,7} , then verify that Axx(BcapC)=(AxxB)cap(AxxC)

If A={1,4},B={2,3,6} and C={2,3,7} , then verify that Axx(BcupC)=(AxxB)cup(AxxC)

Let A={1,2},\ B={1,2,3,4},\ C={5,6}a n d\ D={5,6,7,8} . Verity that: Axx(BnnC)=(AxxB)nn(AxxC)

If A={1,4}B={2,3,6} and C={2,3,7} verify that Axx(B-C)=(AxxB)-(AxxC) .

Let A={1,2},B={1,2,3,4},C={5,6}and D={5,6,7,8}. Verify that: (i) Axx(B nn C)=(AxxB)nn(AxxC) . (ii) AxxC is a subset of BxxD .

If A={2,3},\ B={4,5},\ C={5,6},\ \ find Axx(BuuC),\ Axx(BnnC),\ (AxxB)uu(AxxC)dot

Let A = {1, 2}dot B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8} . Verify that(i) Axx (B nnC) = (A xxB) nn(A xxC) . (ii) A xxC i s a s u b s e t of B xxD .

If A={1,2,3},B={3,4}and C={4,5,6}, "then prove that" (AxxB)uu(AxxC) ={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5 ),(2,6),(3,3),(3,4),(3,5),(3,6)}