Let `f(x)=` minimum `(x+1,sqrt(1-x))` for all `xle1`. Then the area bounded by `y=f(x)` and the x-axis is k units then 6 k is equal to

Let f(x) = minimum (x+1, sqrt(1-x))" for all "x le 1. Then the area bounded by y=f(x) and the x-axis is

Let f(x)=min (x+1,sqrt(1-x)) for all xlt=1. Then the area bounded by y=f(x) and the x-axis is (a) 7/3 sq units (b) 1/6 sq units (c) (11)/6 sq units (d) 7/6 sq units

The area bounded by y=1-|x| and X-axis is

Consider f(x)= minimum (x+2, sqrt(4-x)), AA x le 4 . If the area bounded by y=f(x) and the x - axis is (22)/(k) square units, then the value of k is

Let f(x)= minimum {e^(x),3//2,1+e^(-x)},0lexle1 . Find the area bounded by y=f(x) , X-axis and the line x=1.

The area bounded by y=||x|-1| with the x - axis from x =0 to x=1 is k square units, then 4k is equal to

Let f(x)=min(x+1,sqrt(1-x))AA x le 1 . Then, the area (in sq. units( bounded by y=f(x), y=0 and x=0 from y=0 to x=1 is equal to

The area bounded by the parabola y=(x-4)(x-1) and X-axis is

Let f be a real - valued function defined on R ( the set of real numbers) such that f(x) = sin^(-1) ( sin x) + cos^(-1) ( cos x) The area bounded by curve y = f(x) and x- axis from pi/2 le x le pi is equal to

The area bounded by the curve y=x^(2)(x-1)^(2) with the x - axis is k sq. units. Then the value of 60 k is equal to